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Question

Physics Question on cells

A battery of emf 10V10\, V and internal resistance 3Ω3\, \Omega is connected to a resistor. The current in the circuit is 0.5A0.5\, A. The terminal voltage of the battery when the circuit is closed is

A

10 V

B

0 V

C

1.5 V

D

8.5 V

Answer

8.5 V

Explanation

Solution

Terminal voltage of the battery after closing the circuit is V=EirV = E-ir =100.5×3= 10-0.5\times 3 =101.5=10-1.5 =8.5V=8.5\,V