Question

A battery of 6 volts is connected to the terminals of a three metre long wire of uniform thickness and resistance of the order of 100$\Omega$. The difference of potential between two points separated by 50 on the wire will be

• A. 1 V
• B. 1.5 V
• C. 2 V
• D. 3 V

Answer 1

Answer: (A)

1 V

Answer 2

Here same current is passing throughout the length of the wire, hence $V \propto R \propto l$

⇒ $\frac { 6 } { V _ { 2 } } = \frac { 300 } { 50 }$ ⇒ V₂ =1 V.