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Question: A battery is connected to a potentiometer and a balance point is obtained at 84 cm along the wire. W...

A battery is connected to a potentiometer and a balance point is obtained at 84 cm along the wire. When its terminals are connected by a 5Ω5 \Omega resistor, the balance point changes to 70 cm. Find the new position of the balance point when 5Ω5 \Omega resistor is changed by 4Ω4 \Omega resistor.
A. 26.5 cm
B. 52 cm
C. 67.2 cm
D. 83.3 cm

Explanation

Solution

To solve this problem, use the formula for internal resistance. Substitute the values in the formula of internal resistance for 5Ω5 \Omega resistor and calculate the internal resistance for it. Then, use the same formula to find the internal resistance for 4Ω4 \Omega resistor. Substitute the internal resistance obtained above in this equation and find the unknown variable which is the new position of the balance point.
Formula used:
r=l1l2l2Rr= \dfrac {{l}_{1}-{l}_{2}}{{l}_{2}}R

Complete answer:
Given: l1=84cm{l}_{1}= 84 cm
l2=70cm{l}_{2}= 70 cm
R1=5Ω{R}_{1}= 5 \Omega
R2=4Ω{R}_{2}= 4 \Omega
The formula for internal resistance is given by,
r=l1l2l2Rr= \dfrac {{l}_{1}-{l}_{2}}{{l}_{2}}R
Internal resistance when 5Ω5 \Omega resistor is connected is given by,
r=l1l2l2R1r= \dfrac {{l}_{1}-{l}_{2}}{{l}_{2}}{R}_{1}
Substituting values in above equation we get,
r=847070×5r= \dfrac {84-70}{70}\times 5
r=1470×5\Rightarrow r= \dfrac {14}{70}\times 5
r=1Ω\Rightarrow r= 1 \Omega
Internal resistance when 4Ω4 \Omega resistor is connected is given by,
r=l1l3l3R2r= \dfrac {{l}_{1}-{l}_{3}}{{l}_{3}}{R}_{2}
Substituting values in above equation we get,
1=84l3l3×41= \dfrac {84-{l}_{3}}{{l}_{3}} \times 4
l3=(84l3)×4\Rightarrow {l}_{3}=(84-{l}_{3}) \times 4
l3=3364l3\Rightarrow {l}_{3}= 336 – 4{l}_{3}
5l3=336\Rightarrow 5{l}_{3}= 336
l3=3365\Rightarrow {l}_{3}= \dfrac {336}{5}
l3=67.2cm\Rightarrow {l}_{3}= 67.2 cm
Hence, when 5Ω5 \Omega resistor is changed by 4Ω4 \Omega resistor, the new position of the balance point is 67.2 cm.

So, the correct answer is option C i.e. 67.2 cm.

Note:
Internal resistance is the opposition offered by the cells and batteries to the flow of current flowing in the generation of heat. Internal resistance depends upon the nature of the material of the wire. The potentiometer is an arrangement that can be used to find the unknown value of resistances and the cell’s internal resistance. Potentiometer is also used to determine the unknown values of potential differences.