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Question: A battery is connected between two points A and B on the circumference of a uniform conducting ring ...

A battery is connected between two points A and B on the circumference of a uniform conducting ring of radius r and resistance R. One of the arcs ABA B of the ring subtends an angle θ\theta at the centre. The value of, the magnetic induction at the centre due to the current in the ring is

A

Proportional to 2(180θ)2 \left( 180 ^ { \circ } - \theta \right)

B

Inversely proportional to r

C

Zero, only if θ=180\theta = 180 ^ { \circ }

D

Zero for all values of θ\theta

Answer

Zero for all values of θ\theta

Explanation

Solution

Directions of currents in two parts are different, so directions of magnetic fields due to these currents are different.

Also applying Ohm's law across ABA B

i1R1=i2R2i1l1=i2l2i _ { 1 } R _ { 1 } = i _ { 2 } R _ { 2 } \Rightarrow i _ { 1 } l _ { 1 } = i _ { 2 } l _ { 2 } …..(i)

Also B1=μ04π×i1l1r2B _ { 1 } = \frac { \mu _ { 0 } } { 4 \pi } \times \frac { i _ { 1 } l _ { 1 } } { r ^ { 2 } } and ;

B2B1=i1l1i2l2=1\frac { B _ { 2 } } { B _ { 1 } } = \frac { i _ { 1 } l _ { 1 } } { i _ { 2 } l _ { 2 } } = 1 [Using (i)]

Hence, two field are equal but of opposite direction. So, resultant magnetic induction at the centre is zero and is independent of θ\theta .