Question

A batsman scores runs in 10 innings 38, 70, 48, 34, 42, 55, 63, 46, 54, 44, then the mean deviation is

• A. 8.6
• B. 6.4
• C. 10.6
• D. 9.6

Answer 1

Answer: (A)

8.6

Answer 2

Arranging the given data in ascending order, we have

34, 38, 42, 44, 46, 48, 54, 55, 63, 70,

Here median M =$\frac{46 + 48}{2} = 47$

$(\because n = 10,$ median is the mean of 5^th and 6^th items)

$\therefore$ Mean deviation $= \frac{\Sigma|x_{i} - M|}{n}$

$= \frac{\Sigma|x_{i} - 47|}{10} = \frac{13 + 9 + 5 + 3 + 1 + 1 + 7 + 8 + 16 + 23}{10} = 8.6$