Question

A batsman scores runs in 10 innings 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44, then the mean deviation is

• A. 8.6
• B. 6.4
• C. 10.6
• D. 9.6

Answer 1

Answer: (A)

8.6

Answer 2

Arranging the given data in ascending order, we have 34, 38, 42, 44, 46, 48, 54, 55, 63, 70 Here, Median ${M} = \frac{46 + 48}{2} = 47$ ($\because$ n = 10, median is the mean of 5th and 6th items) $\therefore$ Mean deviation = $\frac{\sum \left| {x_{i} -M}\right|}{ {n}}=\frac{\sum \left| {x_{i}}-47\right|}{10}$ $= \frac{13 + 9 +5+3+1+1+7+8+16+23}{10} = 8.6$