Question: A bar of cross – section A is subjected to equal and opposite tensile forces F at its ends. Consider...

Question

A bar of cross – section A is subjected to equal and opposite tensile forces F at its ends. Consider a plane through the bar making an angle θ with a plane at right angle to the bar. Then shearing stress

will be maximum if θ

Answer 1

Solution

Shear stress = $\frac{F\sin\theta}{A/\cos\theta} = \frac{F\sin 2\theta}{2A}$

Shear stress will be maximum if sin 2θ = 1 or 2θ = 90⁰

i.e., θ = 45⁰.