Solveeit Logo
Login

Question

Question: A bar magnet when placed at an angle of 30º to the direction of magnetic field induction of 5 × 10<s...

A bar magnet when placed at an angle of 30º to the direction of magnetic field induction of 5 × 10–-4 T, experiences a moment of couple 25 × 10–6 N-m. If the length of the magnet is 5 cm, its pole strength is-

A

2 × 10–2 A-m

B

50 × 10–2 A-m

C

2 A-m

D

5 A-m

Answer

2 A-m

Explanation

Solution

t = MB sin q ̃ M =

m × l =

\ m = τℓBsin⁡θ\frac { \tau } { \ell \mathrm { B } \sin \theta }