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Question

Physics Question on Moving charges and magnetism

A bar magnet of magnetic moment M is placed in the magnetic field B. The torque acting on the magnet is.

A

M×BM\times B

B

MBM-B

C

12M×B\frac{1}{2}M\times B

D

M+BM+B

Answer

M×BM\times B

Explanation

Solution

Torque is equal to instantaneous moment of deflecting couple . The torque acting is given by τ=\tau = force (F1=F2)×({{F}_{1}}={{F}_{2}})\times perpendicular distance τ=iBl×bsinθ\tau =iBl\times b\sin \theta Where ii is current, B is magnetic field, ll the length and b the distance the term ilb=M=ilb=M= dipole moment τ=MBsinθ\tau =MB\,sin\theta τ=M×B\tau =M\times B