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Question

Physics Question on Magnetism and matter

A bar magnet of magnetic moment M, is placed in a magnetic field of induction B. The torque exerted on it is

A

M×BM\times B

B

BM-B\cdot M

C

MBM \cdot B-

D

MBM \cdot B

Answer

M×BM\times B

Explanation

Solution

When a bar magnet of magnetic moment M, is placed in a magnetic field of induction B, then net force on it is
FR=mB+(m)B=0F_R = mB + (-m )B = 0

while torque
τ=mB×2lsinθ=MBsinθ\tau = mB \times 2lsin\, \theta = MB \,sin \,\theta
i.e. τ=M×B\tau=M\times B