Question

A bar magnet is placed upright on a floor (so that the axis of the magnet is vertical). A copper ring is held above the magnet, with its plane horizontal and released. The copper ring falls in such a manner that its axis always coincides with that of the magnet. What will be the acceleration with which the ring will fall? Acceleration due to gravity is $10\,m/s^{2}$ .

• A. $10\,m/s^{2}$
• B. Less than $10\,m/s^{2}$
• C. More than $10\,m/s^{2}$
• D. the answer will depend upon which pole of the magnet is up

Answer 1

Answer: (B)

Less than $10\,m/s^{2}$

Answer 2

The acceleration with which the ring will fall will be class than $10\, m / s ^{2}$.