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Question

Physics Question on beats

A band playing music at a frequency f is moving towards a wall at a speed vbv_b. A motorist is following the band with a speed vmv_m. If v be the speed of the sound, the expression for beat frequency heard by motorist is

A

v+vmv+vbf\frac{v+v_{m}}{v+v_{b}} f

B

v+vmvvbf\frac{v +v_{m}}{v-v_{b}} f

C

2vb(v+vm)v2vb2f\frac{2 v_{b}\left(v+v_{m}\right)}{v^{2}-v_{b}^{2}} f

D

2vm(v+vb)v2vm2f\frac{2 v_{m}\left(v+v_{b}\right)}{v^{2} - v_m^2} f

Answer

2vb(v+vm)v2vb2f\frac{2 v_{b}\left(v+v_{m}\right)}{v^{2}-v_{b}^{2}} f

Explanation

Solution

According to Doppler's effect When observer is moving behind the source (band),apparent frequency heard n=n[v+vov+vs]n'=n\left[\frac{v+v_{o}}{v+v_{s}}\right] Here, vo=vmv_{o}=v_{m} vs=vbv_{s}=v_{b} n1=[v+vmv+vb]f\therefore n_{1}=\left[\frac{v+v_{m}}{v+v_{b}}\right] f The other sound is echo, reaching the observer from the wall and can be regarded as coming from the image of source formed by reflection at the wall. This image is approaching the observer in the direction of sound. Hence, for reflected sound, frequency heard by motorist n2=n[v+vovvs]n_{2}=n\left[\frac{v+v_{o}}{v-v_{s}}\right] or n2=f[v+vmvvb]n_{2}=f\left[\frac{v+v_{m}}{v-v_{b}}\right] Then, number of beat frequency heard by motorist =n2n1.=n_{2}-n_{1} . n2n1=(v+vmvvb)f(v+vmv+vb)fn_{2}-n_{1}=\left(\frac{v+v_{m}}{v-v_{b}}\right) f-\left(\frac{v+v_{m}}{v+v_{b}}\right) f =2vb(v+vm)v2vb2f=\frac{2 v_{b}\left(v+v_{m}\right)}{v^{2}-v_{b}^{2}} f