Question
Question: A balloon filled with helium gas rises a certain height at which it gets fully inflated to a volume ...
A balloon filled with helium gas rises a certain height at which it gets fully inflated to a volume of 1×105 litres. If at this altitude temperature and atmospheric pressure is 268K and 2×10−3 atm respectively. What will be the weight if helium will be required to fully inflate the balloon?
Solution
Ideal gas equation is an equation of hypothetical gas. It helps in telling us the behaviour of gases under several conditions.
-Mole concept gives us the relation between the number of moles, weight and the molar mass of a given compound.
Formula used:
PV=nRT
Where, P is the pressure
V is the volume
n is the number of moles
R is the universal gas constant
T is the temperature
The weight can be calculated by the product of the number of moles and molar mass
w=n×m
w Is the weight
m Is the molar mass
n Is the number of moles
Complete step by step answer:
According to the ideal gas equation:
The product of pressure and volume gives us the relation between the product of gas constant and temperature.
Here, it is given that the volume of the helium gas in balloon is 1×105
The given temperature is 268K
The given pressure is 2×10−3
PV=nRT
Where, P is the pressure
n Is the number of moles
V Is the volume
T Is the temperature
R Is the gas constant
Now, substituting the values in above formula we get,
2×10−3×105=n×0.0821×268
On further solving ,
n=9.08 mol
The weight can be calculated by the product of the number of moles and molar mass
w=n×m
Where, n is the number of moles
w is the weight
m is the molar mass
The molar mass of helium is 4g
On substituting the above value in this formula we get,
w=9.08×4
w=36.32g
Therefore, the weight of helium to fully inflate the balloon is 36.32g.
Note:
-The number of moles is defined as the weight per molar mass of the given compound.
-Ideal gas equation tells the behaviour of gases under many conditions.
-Here, the value of universal gas constant is 0.0821 latmmol−1K−1