Question

A balloon contains 1500 m3 of helium at 27°C and 4 atmospheric pressure. The volume of helium at –3°C temperature and 2 atmospheric pressure will be

• A. 1500 m3
• B. 1700 m3
• C. 1900 m3
• D. 2700 m3

Answer 1

Answer: (D)

2700 m3

Answer 2

Here, $V_{1} = 1500m^{3},T_{1} = 27{^\circ}C = 300K$

$P_{1} = 4atm,T_{2} = - 3{^\circ}C = 270K$

$P_{2} = 2atm$

According to ideal gas equations

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

$\therefore V_{2} = \frac{P_{1}V_{1}}{T_{1}} \times \frac{T_{2}}{P_{2}} = \frac{4 \times 1500 \times 270}{300 \times 2} = 2700m^{3}$