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Question

Physics Question on System of Particles & Rotational Motion

A ballet dancer, dancing on a smooth floor is spinning about a vertical axis with her arms folded with an angular velocity of 20rad/s20 \,rad/s. When she stretches her arms fully, the spinning speed decrease as 10rad/s10\, rad/s. If II is the initial moment of inertia of the dancer, the new moment of inertia is

A

2I2I

B

3I3I

C

I/2I/2

D

I/3I/3

Answer

2I2I

Explanation

Solution

Here, angular momentum is conserved. Initial angular momentum = Final angular momentum I×20=I×10I \times 20 = I' \times 10, where II' is new moment of inertia I=2I\therefore I' = 2I