Question

A ball whose kinetic energy is E, is projected at an angle of 45⁰ to the horizontal. The kinetic energy of the ball at the highest point of its flight will be –

• A. E
• B. $E/\sqrt{2}$
• C. E/2
• D. Zero

Answer 1

Answer: (B)

$E/\sqrt{2}$

Answer 2

K.E. at max. height = K cos²q