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Question: A ball of mass \(m_{1}\) and another ball of mass \(m_{2}\) are dropped from equal height. If time t...

A ball of mass m1m_{1} and another ball of mass m2m_{2} are dropped from equal height. If time taken by the balls are t1t_{1} and t2t_{2} respectively, then

A

t1=t22t_{1} = \frac{t_{2}}{2}

B

t1=t2t_{1} = t_{2}

C

t1=4t2t_{1} = 4t_{2}

D

t1=t24t_{1} = \frac{t_{2}}{4}

Answer

t1=t2t_{1} = t_{2}

Explanation

Solution

The time of fall is independent of the mass.