Question

A ball of mass m is thrown vertically upward. Another ball of mass 2 m is thrown at an angle θ with the vertical. Both the balls stay in air for the same period of time. The ratio of the heights attained by the two balls respectively is 1/x. The value of x is _______.

Answer 1

The correct answer is 1

$∴ u1 = u2\sinθ$
$\frac{H_1}{H_2}=\frac{\frac{u_{1}^{2}}{2g}}{u^{2}_{2}\frac{\sin^2⁡θ}{2g}}$
$=\left(\frac{u_1}{u_2\sinθ}\right)^2=1$