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Question: A ball of mass m is released from A inside a smooth wedge of mass m as shown in the figure. What is ...

A ball of mass m is released from A inside a smooth wedge of mass m as shown in the figure. What is the speed of the wedge when the ball reaches point B?

A

(gR32)1/2\left( \frac { \mathrm { gR } } { 3 \sqrt { 2 } } \right) ^ { 1 / 2 }

B

2gR\sqrt { 2 \mathrm { gR } }

C

(5gR23)1/2\left( \frac { 5 \mathrm { gR } } { 2 \sqrt { 3 } } \right) ^ { 1 / 2 }

D

32gR\sqrt { \frac { 3 } { 2 } \mathrm { gR } }

Answer

(gR32)1/2\left( \frac { \mathrm { gR } } { 3 \sqrt { 2 } } \right) ^ { 1 / 2 }

Explanation

Solution

0 = 12mvrel2\frac { 1 } { 2 } \mathrm { mv } _ { \mathrm { rel } } ^ { 2 } + 12mv2\frac { 1 } { 2 } \mathrm { mv } ^ { 2 } – mgRcos450

0 = 1/2 m (v2+u2 – 2uvcos 450) + 1/2 mv2 – mgRcos450.... (1)

pi = pf ̃ = – mv+ m(ucos450 – v) ….(2)