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Question: A ball of mass M falls from a height h on a floor which the coefficient of restitution is e. The hei...

A ball of mass M falls from a height h on a floor which the coefficient of restitution is e. The height attained by the ball after two rebounds is:

A

e2he^{2}h

B

eh2eh^{2}

C

e4he^{4}h

D

he4\frac{h}{e^{4}}

Answer

e4he^{4}h

Explanation

Solution

A ball falling from height h reaches the floor with velocity

v=2ghv = \sqrt{2gh}

By definition

e=velocityofseparationvelocityofapproache = \frac{velocityofseparation}{velocityofapproach}

\thereforeRebound velocity =e2ghe\sqrt{2gh}

\thereforeRebound height = e2h

After two rebounds, height = e4he^{4}h