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Question: A ball of mass 0.2 kg moves with a velocity of 20 m/sec and it stops in 0.1 sec; then the force on t...

A ball of mass 0.2 kg moves with a velocity of 20 m/sec and it stops in 0.1 sec; then the force on the ball is

A

40 N

B

20 N

C

4 N

D

2 N

Answer

40 N

Explanation

Solution

F=maF = ma =mΔvΔt=0.2×200.1=406muN= \frac{m\Delta v}{\Delta t} = \frac{0.2 \times 20}{0.1} = 40\mspace{6mu} N