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Question

Physics Question on laws of motion

A ball of mass 0.5kg0.5\, kg moving with a velocity of 2ms12 \,ms ^{-1} strikes a wall normally and bounces back with the same speed. If the time of contact between the ball and wall is 103s10^{-3} s, the average force exerted by the wall on the ball is

A

1125 N

B

1000 N

C

500 N

D

2000 N

Answer

2000 N

Explanation

Solution

Impulse =mv(mv)=m v -(-m v) =0.5×2(0.5×2)=2=0.5 \times 2-(-0.5 \times 2)=2 Hence, F=2103=2000NF =\frac{2}{10^{-3}}=2000\, N