Question

A ball of mass 0.5 kg is dropped from the height of 10 m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ___ m.
[Use g = 10 m/s2]

Answer 1

$gt = g$
$⇒ t = 1 sec$
$\Delta h = \frac{1}{2}gt^2 = \frac{1}{2} \times 5 \times 12^2 = 5 \, \text{m}$
$∴$ $h = H – Δh$
$= 10 – 5 = 5 m$