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Question

Physics Question on Gravitation

A ball of mass 0.150.15 kgkg hits the wall with its initial speed of 1212 ms1ms^{–1} and bounces back without changing its initial speed. If the force applied by the wall on the ball during the contact is 100100 NN, calculate the time duration of the contact of ball with the wall.

A

0.018 s

B

0.036 s

C

0.009 s

D

0.072 s

Answer

0.036 s

Explanation

Solution

Force applied by the wall on the ball during the contact is = 100100 NN

\Rightarrow ΔP=2×0.15×12ΔP = 2 × 0.15 × 12

=3.6= 3.6

Hence, t=3.6100t = \frac{3.6}{100}

= 0.0360.036 ss

Hence, the correct option is (B): 0.036  s0.036\;s