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Question

Physics Question on work, energy and power

A ball moving with velocity 2m/s2\, m/s collides head on with another stationary ball of double the mass. If the coefficient of restitution is 0.50.5, then their velocities (inm/s)(in\, m/s) after collision will be

A

0, 1

B

44562

C

1, 0.5

D

0, 2

Answer

0, 1

Explanation

Solution

Here, m1_1 = w, m2_2 = 2m
u1_1= 2 m/s, u2_2 = 0
Coefficient of restitution, e = 0.5
Let v1_1 and v2_2 be their respective velocities after collision.
Applying the law of conservation of linear momentum, we get
m1u1+m2u2=m1v1+m2v2m_1u_1+m_2u_2=m_1v_1+m_2v_2
m×2+2m×0=m×v1+2m×v2\therefore m \times 2 +2m \, \, \times \, 0 = m\times v_1 +2m \times v_2
or 2m=mv1+2mv22m = mv_1 + 2mv_2
or 2 = (v1v_1 + 2v2)v_2) ...(i)
By definition of coefficient of restitution,
e=v2v1u1u2e=\frac{v_2 -v_1}{u_1 -u_2}
or e(u1u2)=v2v1e(u_1 -u_2)=v_2-v_1
0.5(2 - 0) = v2v1v_2 - v_1 ...(ii)
1=v2v11=v_2-v_1
Solving equations (i) and (ii), we get
v1=0m/sv_1 = 0\, m/s, v2=1m/sv_2 = 1\, m/s