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Question

Physics Question on Elastic and inelastic collisions

A ball moving with a velocity vv hits a massive wall moving towards the ball with a velocity uu . An elastic impact lasts for a time Δt\Delta t .

A

the average elastic force acting on the ball is m(u+v)Δt\frac{m \left(u + v\right)}{\Delta t}

B

the average elastic force acting on the ball is 2m(u+v)Δt\frac{2 m \left(u + v\right)}{\Delta t}

C

the kinetic energy of the ball increases by mu(u+v)mu\left(u + v\right)

D

the kinetic energy of the ball remains the same after the collision.

Answer

the average elastic force acting on the ball is 2m(u+v)Δt\frac{2 m \left(u + v\right)}{\Delta t}

Explanation

Solution

As the wall is massive its velocity remains unchanged. Speed of the ball after impact vˉf=v+2u\bar{v}_{f}=v+2u The average elastic force acting on the ball is, Fˉ=mΔvˉΔt=m[vˉfvˉi]Δt\bar{F}=\frac{m \Delta \bar{v}}{\Delta t}=\frac{m \left[\bar{v}_{f} - \bar{v}_{i}\right]}{\Delta t} F=m[(v+2u)(v)]Δt=2m(u+v)ΔtF=\frac{m \left[\left(v + 2 u\right) - \left(- v\right)\right] \, }{\Delta t}=\frac{2 m \left(u + v\right)}{\Delta t} F=2m(u+v)ΔtF=\frac{2 m \left(u + v\right)}{\Delta t}