Question
Question: A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate (1) The maximum height to...
A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate
(1) The maximum height to which it rises.
(2) The total time it takes to return to the surface of the earth.
Solution
The rate of change of an object's location with regard to a frame of reference is its velocity, which is a function of time. A definition of an object's speed and direction of travel (e.g. 60 km/h to the north) is identical to velocity. In kinematics, the branch of classical mechanics that explains the motion of bodies, velocity is a basic notion. We use equations of motion to solve the problem.
Formula Used:
2gs = v2− u2
G = acceleration due to gravity
V = final velocity
U = initial velocity
S = displacement
Complete answer:
Velocity is a physical vector quantity that requires both magnitude and direction to define. Speed is the scalar absolute value (magnitude) of velocity, and it is a coherent derived unit whose quantity is measured in metres per second (m/s) in the SI (metric system).
The ball's initial velocity (u) is 49 metres per second.
The ball's greatest height velocity (v) Equals 0.
g = 9.8ms−2
Let us consider the time is t to reach the maximum height H.
Consider a formula,
2gs = v2− u2
Hence upon substituting
2 × (− 9.8) × H = 0 − (49)2
so
– 19.6 H = – 2401
We get
⇒H = 122.5 m
Now consider a formula,
v = u + g × t
here
0 = 49 + (- 9.8) × t
hence
–49 = – 9.8t
therefore
⇒t = 5 sec
Note: Never forget to memorise the formulae of equations of motion. Equations of motion are physics equations that describe a physical system's behaviour in terms of its motion as a function of time. The equations of motion, more particularly, explain the behaviour of a physical system as a collection of mathematical functions expressed in terms of dynamic variables. Typically, these variables are geographical coordinates and time, but they may also incorporate momentum components.