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Question

Physics Question on Motion in a straight line

A ball is thrown from height hh and another from 2h2h The ratio of time taken by the two balls to reach ground is:

A

1:21:\sqrt{2}

B

2:1\sqrt{2}:1

C

2:12 : 1

D

1:21 : 2

Answer

1:21:\sqrt{2}

Explanation

Solution

For first ball, h=0×t1+12gt12h=0 \times t_{1}+\frac{1}{2} g t_{1}^{2} t1=2hg\Rightarrow t_{1} =\sqrt{\frac{2 h}{g}} \ldots(i) For second ball, 2h=0×t212gt222 h=0 \times t_{2}-\frac{1}{2} g t_{2}^{2} t2=4hg\Rightarrow t_{2}=\sqrt{\frac{4 h}{g}} \ldots(ii) From Eqs. (i) and (ii) t1:t2=1:2t_{1}: t_{2}=1: \sqrt{2}