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Question: A ball is projected with kinetic energy \(E\)at an angle of \(45^{o}\) to the horizontal. At the hig...

A ball is projected with kinetic energy EEat an angle of 45o45^{o} to the horizontal. At the highest point during its flight, its kinetic energy will be

A

Zero

B

E2\frac{E}{2}

C

E2\frac{E}{\sqrt{2}}

D

EE

Answer

E2\frac{E}{2}

Explanation

Solution

E′=Ecos⁡2θ=Ecos⁡2(45∘)=E2E' = E\cos^{2}\theta = E\cos^{2}(45{^\circ}) = \frac{E}{2}