Question
Question: A ball is projected with a velocity 20 ms<sup>–1</sup> at an angle to the horizontal. In order to ha...
A ball is projected with a velocity 20 ms–1 at an angle to the horizontal. In order to have the maximum range, its velocity at the highest position must be –
A
10 ms–1
B
14 ms–1
C
28 ms–1
D
Zero
Answer
14 ms–1
Explanation
Solution
For maximum range q = 450
Hence velocity at highest point = u cos 450
= 20 ×21= 14 m/s.