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Question

Physics Question on projectile motion

A ball is projected vertically upwards from a building. The time taken to reach ground is T1. Another ball is projected downwards from the same building, with the same speed. The time taken to reach ground is T2. If a third ball is released from the same building, the time taken to reach the ground is

A

T1T2\sqrt{T_1T_2}

B

T12+T22\sqrt{T_1^2+T_2^2}

C

T12T22\sqrt{T_1^2-T_2^2}

D

2T1T22\sqrt{T_1T_2}

Answer

T1T2\sqrt{T_1T_2}

Explanation

Solution

The Correct answer is option is (A) : T1T2\sqrt{T_1T_2}