Question

A ball is projected from the ground with a speed $15\, ms ^{-1}$ at an angle $\theta$ with horizontal so that its range and maximum height are equal, then'tan $\theta$ ' will be equal to

• A. $\frac{1}{4}$
• B. $\frac{1}{2}$
• C. 2
• D. 4

Answer 1

Answer: (D)

4

Answer 2

The correct answer is (D) : 4
R=H
g2vx​×vy​​=2gvy2​​
vx​=4vy​​;ucosθ=4usinθ​
tanθ=4