Question

A ball is projected from a certain point on the surface of a planet at a certain angle with the horizontal surface. The horizontal and vertical displacements x and y vary with time t in second as : x = 10$\sqrt{3}$t ; y = 10t – t². The maximum height attained by the ball is-

• A. 100 m
• B. 75 m
• C. 50 m
• D. 25 m

Answer 1

Answer: (D)

25 m

Answer 2

y = 10t – t²

y is maximum when $\frac { \mathrm { dy } } { \mathrm { dt } }$ = 0