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Question: A ball is dropped on a floor from a height of 2m. After the collision it rises upto a height of 1m. ...

A ball is dropped on a floor from a height of 2m. After the collision it rises upto a height of 1m. Assuming that 20%20\% of mechanical energy is lost in the form of thermal energy. If the specific heat capacity of the ball is 800J/K800J/K then the rise in temperature of the ball during collision is (Take g=10m/s2g = 10m/{s^2}).
A. 2.5×10−32.5 \times {10^{ - 3}} oC^oC
B. 7.5×10−37.5 \times {10^{ - 3}} oC^oC
C. 1.5×10−31.5 \times {10^{ - 3}} oC^oC
D. 5×10−35 \times {10^{ - 3}} oC^oC

Explanation

Solution

As initially ball is at height of 2m and after collision ball height becomes 1m. So after collision loss in potential energy will increase the thermal energy of the ball i.e. decrease in potential energy will be the cause of increase in temperature. Hence change in potential energy will be equal to thermal energy.
Mathematically mg(h1−h2)=msΔTmg({h_1} - {h_2}) = ms\Delta T.

Complete step by step answer:
As we already know that change is potential energy will be equal to increase in thermal energy
∴\therefore given only 20% 0f mechanical energy will be convert into thermal energy
Hence, we apply the equation: mg(h1−h2)×20100=msΔTmg({h_1} - {h_2}) \times \dfrac{{20}}{{100}} = ms\Delta T.
In the above equation m=mass of balL
g= acceleration due to gravity
h1{h_1}=initial height
h2{h_2}=final height
s=specific heat capacity
ΔT\Delta T=change in temperature of body
So after putting all given values in the above equation:
mg(2−1)×20100=m×800×ΔT   mg(2 - 1) \times \dfrac{{20}}{{100}} = m \times 800 \times \Delta T \\\ \\\ here g=10ms−2g = 10m{s^{ - 2}}
m×10×15=m×800×ΔTm \times 10 \times \dfrac{1}{5} = m \times 800 \times \Delta T
2=800×ΔT2 = 800 \times \Delta T
ΔT=2800\Delta T = \dfrac{2}{{800}}
ΔT=2.5×10−3\Delta T = 2.5 \times {10^{ - 3}}
Hence, increase in temperature of ball be 2.5×10−32.5 \times {10^{ - 3}}
Option number A will be the correct option.

Note: Potential energy is the energy of the body associated with height of the body i.e. if a body will be more height from the surface of the earth then it will have more potential energy and if the body has more potential energy then it will have more mechanical energy.
Thermal energy is the energy of the body associated with the temperature of the body, thermal energy also depends on the specific heat of the body.