Question

A ball is dropped from top of a tower of height 'h'. It takes time 'T' to reach ground. What is height of the body from ground at time 'T/4' ?

• A. $\frac{h}{16}$
• B. $\frac{8h}{9}$
• C. $\frac{h}{4}$
• D. $\frac{15h}{16}$

Answer 1

Answer: (D)

$\frac{15h}{16}$

Answer 2

Q h = $\frac{1}{2}$gT² …….(1)

\ T = $\sqrt{\frac{2h}{g}}$

Displacement of ball in time T/4

S = $\frac{1}{2}$g(T/4)² = $\frac{h}{16}$

\ Height from ground = h – $\frac{h}{16}$ = $\frac{15}{16}h$