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Question

Physics Question on work, energy and power

A ball is dropped from a height of 5 m on a planet where the acceleration due to gravity is not known. On bouncing it rises to 1.8 m. The ball loses its velocity on bouncing by a factor of

A

16/25

B

44597

C

44625

D

44806

Answer

44597

Explanation

Solution

Using, υ2−u2=2gh\upsilon^2 - u^2 = 2gh, we get υ=2gh\upsilon = \sqrt{2gh} ∴ υ2υ1=h2h1=1.85=35\therefore\,\frac{\upsilon_2}{\upsilon_1} = \sqrt{\frac{h_2}{h_1}} = \sqrt{\frac{1.8}{5}} = \frac{3}{5}
Loss in velocity = υ1−υ2υ1=υ1−υ2υ1=1−35=25\frac{\upsilon_1 - \upsilon_2}{\upsilon_1} = \upsilon_1 - \frac{\upsilon_2}{\upsilon_1} = 1 - \frac{3}{5} = \frac{2}{5}