Question
Question: A ball is dropped from a height \[h\] As it bounces off the floor, its speed becomes \[80\% \] of wh...
A ball is dropped from a height h As it bounces off the floor, its speed becomes 80% of what it was just before it hit the floor. The ball then rises to a height equal to
A. 0.8h
B. 0.75h
C. 0.64h
D. 0.50h
Solution
We are asked to find the height to which the ball rises. We can start by noting down the given data. We can then move onto finding the final velocity using one of the equations of motion. Then we move onto finding the final velocity at the given speed using the formula. Then we can find the value of distance using one of the equations of motion.
Formulas used:
The formula used to find the final velocity when the initial velocity is zero is,
v=−2gh
The formula used to find the distance is given by,
v2=u2+2ah
Where, h is the height from which the ball is dropped and u is the initial velocity of the ball.
Complete step by step answer:
Let us start by writing down the given information. The height from which the ball is dropped is given as, h. Since the ball is dropped and not thrown, the initial velocity of the ball will be u=0. The speed becomes 80% of what it was just before it hit the floor.Now we can move onto finding the final velocity using the formula,
v=−2gh
We can multiply this with the percentage value with the velocity and get the final value.That is,
v=−0.82gh
Now this value can be substituted in the formula, v2=u2+2ah and find the value of distance.