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Question: A ball is bouncing down a flight of stairs. The coefficient of restitution is \(e\). The height of e...

A ball is bouncing down a flight of stairs. The coefficient of restitution is ee. The height of each step is dd and the ball descends one step each bounce. After each bounce it rebounds to a height hh above the next lower step. The height is large compared with the width of the step so that the impacts are effectively head-on. Find the relationship between hh and dd.
(A) h=d1e2h = \dfrac{d}{{1 - {e^2}}}
(B) h=d1+e2h = \dfrac{d}{{1 + {e^2}}}
(C) h=d1+eh = \dfrac{d}{{1 + {e^{}}}}
(D) h=d1e2h = \sqrt {\dfrac{d}{{1 - {e^2}}}}

Explanation

Solution

Hint
We are here asked to find the relationship between hh and dd. Also we are given with the coefficient of restitution. Thus, it would be easier to go through the path of restitution analysis.
v2u2=2ah{v^2} - {u^2} = 2ah
Where, vv is the final velocity of the particle, uu is the initial velocity of the particle, aa is the acceleration on it and hh is the height of the particle.
e=v2v1e = \dfrac{{{v_2}}}{{{v_1}}}
Where, ee is the coefficient of restitution, v2{v_2} is the velocity of the particle after collision and v1{v_1} is the velocity of the particle before collision.

Complete step by step answer
Here, For the first bounce of the ball on the top most step,
v1202=2ah{v_1}^2 - {0^2} = 2ah
We took u1=0{u_1} = 0 as the initial velocity of the ball was zero.
Thus, we get
2ah=v12(1)2ah = {v_1}^2 \cdot \cdot \cdot \cdot (1)
Now, After the first bounce, the new height of the ball is (hd)(h - d),
Thus, we get
2a(hd)=v22(2)2a(h - d) = {v_2}^2 \cdot \cdot \cdot \cdot (2)
Now,
ApplyingEquation(1)Equation(2)\dfrac{{Equation(1)}}{{Equation(2)}}, we get
hhd=v12v22\dfrac{h}{{h - d}} = \dfrac{{{v_1}^2}}{{{v_2}^2}}
After further evaluation, we get
v2v1=hdh\dfrac{{{v_2}}}{{{v_1}}} = \sqrt {\dfrac{{h - d}}{h}}
But,
e=v2v1e = \dfrac{{{v_2}}}{{{v_1}}}
Thus, equating both, we get
e=hdhe = \sqrt {\dfrac{{h - d}}{h}}
Further, we get
e2=hdhhe2=hdh=d1e2{e^2} = \dfrac{{h - d}}{h} \Rightarrow h{e^2} = h - d \Rightarrow h = \dfrac{d}{{1 - {e^2}}}
Hence, the correct option is (A).

Note
We have used the route of using the fundamental formula for coefficient of restitution as that allows us to directly relate all the given parameters. Moreover, in the given case it is given that the collision is head on which means completely elastic, but if the collision was inelastic, then the evaluation will be somewhat different.