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Question

Physics Question on Motion in a straight line

A ball AA is thrown up vertically with a speed uu and at the same instant another ball BB is released from a height hh. At time tt, the speed of AA relative to BB is

A

uu

B

2u2u

C

ugtu-gt

D

(u2gt)\sqrt{({{u}^{2}}-gt)}

Answer

uu

Explanation

Solution

From equation of motion,
we have v=u+gtv=u+gt
where u is initial velocity and t is time.
For ball A, vA=ugt{{v}_{A}}=u-gt
For ball B, vB=0+gt{{v}_{B}}=0+gt
\therefore Relative speed, Δv=vAvB\Delta \overrightarrow{v}={{\overrightarrow{v}}_{A}}-{{\overrightarrow{v}}_{B}}
=(ugt)j^(gtj^)=(u-gt)\hat{j}-(-gt\,\hat{j})
=uj^=u\hat{j}