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Question

Physics Question on Motion in a straight line

A ball A is dropped from a building of height 45m45\, m . Simultaneously another identical ball BB is thrown up with a speed 50ms150 \,m \,s^{-1} . The relative speed of ball BB w.r.t. ball A at any instant of time is (Take g=10ms2)g = 10\, m \,s^{-2})

A

00

B

10ms110\,m\,s^{-1}

C

25ms125\,m\,s^{-1}

D

50ms150\,m\,s^{-1}

Answer

50ms150\,m\,s^{-1}

Explanation

Solution

Here, uA=0u_A = -0 , uB=+50ms1u_B = +50\, m\, s^{-1} aA=ga_{A}=-g , aB=ga_{B}=-g uBA=uBuA=50ms1(0)ms1=50ms1u_{BA}=u_{B}-u_{A}=50\,m\,s^{-1}-(-0)\,m\,s^{-1}=50\,m\,s^{-1} aBA=aBaA=g(g)=0a_{BA}=a_{B}-a_{A}=-g-\left(-g\right)=0 vBA=uBA+aBAt(AsaBA=0)\because v_{BA}=u_{BA}+a_{BA}t\quad\left(As\,a_{BA}=0\right) vBA=uBA\therefore v_{BA}=u_{BA} As there is no acceleration of ball BB w.r.t to ball AA , therefore the relative speed of ball BB w.r.t ball AA at any instant of time remains constant (=50ms1)( = 50\, m\, s^{-1}) .