Question
Physics Question on Motion in a straight line
A ball A is dropped from a building of height 45m . Simultaneously another identical ball B is thrown up with a speed 50ms−1 . The relative speed of ball B w.r.t. ball A at any instant of time is (Take g=10ms−2)
A
0
B
10ms−1
C
25ms−1
D
50ms−1
Answer
50ms−1
Explanation
Solution
Here, uA=−0 , uB=+50ms−1 aA=−g , aB=−g uBA=uB−uA=50ms−1−(−0)ms−1=50ms−1 aBA=aB−aA=−g−(−g)=0 ∵vBA=uBA+aBAt(AsaBA=0) ∴vBA=uBA As there is no acceleration of ball B w.r.t to ball A , therefore the relative speed of ball B w.r.t ball A at any instant of time remains constant (=50ms−1) .