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Question: A bag P (mass M) hangs by a long thread and a bullet (mass m) comes horizontally with velocity v and...

A bag P (mass M) hangs by a long thread and a bullet (mass m) comes horizontally with velocity v and gets caught in the bag. Then for the combined (beg + bullet) system the

A

Momentum is mvMM+m\frac{mvM}{M + m}

B

Kinetic energy mV22\frac{mV^{2}}{2}

C

Momentum is mv(M+m)M\frac{mv(M + m)}{M}

D

Kinetic energy is m2V22(M+m)\frac{m^{2}V^{2}}{2(M + m)}

Answer

Kinetic energy is m2V22(M+m)\frac{m^{2}V^{2}}{2(M + m)}

Explanation

Solution

Velocity of combined system V=mvm+MV = \frac{mv}{m + M}

Momentum for combined system

=(m+M)V=(m+M)mvm+M= (m + M)V = (m + M)\frac{mv}{m + M}

Kinetic energy for combined system

$$$= \frac{m^{2}v^{2}}{2(m + M)}$.