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Question: A bag of sand of mass 2 kg is suspended by a rope. A bullet of mass 10g is fired at it and gets embe...

A bag of sand of mass 2 kg is suspended by a rope. A bullet of mass 10g is fired at it and gets embedded into it. The bag rises up a vertical height of 10 cm. The initial velocity of the bullet is nearly –

A

70 m/s

B

140 m/s

C

210 m/s

D

280 m/s

Answer

280 m/s

Explanation

Solution

(.01)V + 0 = (2.01)V1

Now 10 C.M. = V122g\frac{V_{1}^{2}}{2g}