Question
Physics Question on laws of motion
A bag is gently dropped on a conveyor belt moving at a speed of 2 m/s. The coefficient of friction between the conveyor belt and bag is 0.4. Initially the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion, is
[Take g = 10 m/s2]
A
2 m
B
0.5 m
C
3.2 m
D
0.8 ms
Answer
0.5 m
Explanation
Solution
The correct option is(B): 0.5 m
v = 2 m/s
μ = 0.4
a = +(0.4) (g)= + 4 m/s2
v 2 – u 2 = 2
⇒ (4) = 2 × (4) (s)
s = 0.5 m