Question
Mathematics Question on Commercial Maths
A bag contains Rs. 216 in the form of one rupee, 50 paise and 25 paise coins in the ratio of 2:3: 4. The number of 50 paise coins is
96
144
114
141
144
Solution
The correct option is (B): 144
Explanation: To solve this problem, let’s denote the number of coins as follows:
- Let the number of 1 rupee coins be x.
- Let the number of 50 paise coins be y.
- Let the number of 25 paise coins be z.
Given that the ratio of the coins is x:y:z=2:3:4, we can express the number of coins as:
- x=2k
- y=3k
- z=4k
where k is a common multiplier.
Now, we can calculate the total value of the coins in rupees:
- Value from 1 rupee coins: 2k×1=2k rupees
- Value from 50 paise coins: 3k×0.50=1.5k rupees
- Value from 25 paise coins: 4k×0.25=k rupees
Now, the total value of the coins is:
2k+1.5k+k=4.5k rupees
Given that the total amount is Rs. 216, we have:
4.5k=216
Solving for k:
k=4.5216=48
Now, we can find the number of 50 paise coins:
y=3k=3×48=144
Thus, the number of 50 paise coins is 144.