Solveeit Logo

Question

Mathematics Question on Commercial Maths

A bag contains Rs. 216 in the form of one rupee, 50 paise and 25 paise coins in the ratio of 2:3: 4. The number of 50 paise coins is

A

96

B

144

C

114

D

141

Answer

144

Explanation

Solution

The correct option is (B): 144
Explanation: To solve this problem, let’s denote the number of coins as follows:
- Let the number of 1 rupee coins be xx.
- Let the number of 50 paise coins be yy.
- Let the number of 25 paise coins be zz.
Given that the ratio of the coins is x:y:z=2:3:4x : y : z = 2 : 3 : 4, we can express the number of coins as:
- x=2kx = 2k
- y=3ky = 3k
- z=4kz = 4k
where kk is a common multiplier.
Now, we can calculate the total value of the coins in rupees:
- Value from 1 rupee coins: 2k×1=2k2k \times 1 = 2k rupees
- Value from 50 paise coins: 3k×0.50=1.5k3k \times 0.50 = 1.5k rupees
- Value from 25 paise coins: 4k×0.25=k4k \times 0.25 = k rupees
Now, the total value of the coins is:
2k+1.5k+k=4.5k rupees2k + 1.5k + k = 4.5k \text{ rupees}
Given that the total amount is Rs. 216, we have:
4.5k=2164.5k = 216
Solving for kk:
k=2164.5=48k = \frac{216}{4.5} = 48
Now, we can find the number of 50 paise coins:
y=3k=3×48=144y = 3k = 3 \times 48 = 144
Thus, the number of 50 paise coins is 144.