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Question: A bag contains 6 red balls and some blue balls, if the probability of drawing a blue ball from the b...

A bag contains 6 red balls and some blue balls, if the probability of drawing a blue ball from the bag is twice that of a red ball, find the number of balls in the bag.

Explanation

Solution

Hint: Assume the number of blue balls be x. Now, the total number of balls that we have is (x+6) balls. Probability of drawing red balls is 6x+6\dfrac{6}{x+6} . We have the probability of drawing blue balls equal to xx+6\dfrac{x}{x+6} . Now, according to the question, it is given that the probability of drawing a blue ball from the bag is twice that of a red ball. Now, solve the equation further.

Complete step-by-step answer:
According to the question, it is given that,
Number of red balls = 6 .
Let us assume the number of blue balls is x.
Total number of balls in the bag= x+6 ………………(1)
We have the number of red balls equal to 6 and number of total balls equal to (x+6) .
Probability of drawing red balls from the bag = numberofredballstotalnumberofballs\dfrac{number\,of\,red\,balls}{total\,number\,of\,balls} .
Probability of drawing red balls from the bag = 6x+6\dfrac{6}{x+6} ……………..(2)
Probability of drawing blue balls from the bag = numberofblueballstotalnumberofballs\dfrac{number\,of\,blue\,balls}{total\,number\,of\,balls} .
Probability of drawing blue balls from the bag = xx+6\dfrac{x}{x+6} …………………..(3)
According to the question, it is given that the probability of drawing a blue ball from the bag is twice that of a red ball.
Probability of drawing blue balls from the bag = 2 ×\times Probability of drawing red balls from the bag
xx+6=2.6x+6\Rightarrow \dfrac{x}{x+6}=2.\dfrac{6}{x+6}
Cancelling the term (x+6) on both sides and solving, we get
x=12\Rightarrow x=12
So, the number of blue balls is 12.
Total number of balls in the bag = 12+6=18.
Hence, the total number of balls in the bag is 18.

Note: In this question one may write,
2 ×\times Probability of drawing blue balls from the bag = Probability of drawing red balls from the bag. This expression is completely wrong. Because the probability of drawing blue balls is already twice that of a red ball. So, to make the probabilities equal we have to multiply by 2 in the probability of drawing red balls from the bag.