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Question

Mathematics Question on Bayes' Theorem

A bag contains 6 balls Two balls are drawn from it at random and both are found to be black The probability that the bag contains at least 5 black balls is

A

27\frac{2}{7}

B

37\frac{3}{7}

C

57\frac{5}{7}

D

56\frac{5}{6}

Answer

57\frac{5}{7}

Explanation

Solution

The correct answer is (C) : 57\frac{5}{7}
5C2+6C22C2+3C2+4C2+5C2+6C2\frac{^5C_2+^6C_2}{^2C_2+^3C_2+^4C_2+^5C_2+^6C_2}
=10+151+3+6+10+15=2535=\frac{10+15}{1+3+6+10+15}=\frac{25}{35}
=57=\frac{5}{7}