A bag contains 5 yellow, 3 green, 2 blue and 7 white balls.... | Mathematics | SolveeIt | Solveeit

Today, August 23

Question

A bag contains 5 yellow, 3 green, 2 blue and 7 white balls. If 4 balls are chosen at random, then the probability that none of them are white is

A

$\frac{3}{37}$

B

$\frac{7}{34}$

C

$\frac{5}{34}$

D

$\frac{5}{37}$

E

$\frac{3}{34}$

Answer

$\frac{3}{34}$

Explanation

Solution

The correct option is (E): $\frac{3}{34}$