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Question: A bag contains 5 balls all of different colours (one of which is white) three persons A, B and C who...

A bag contains 5 balls all of different colours (one of which is white) three persons A, B and C whose probabilities of speaking truth are 12\frac { 1 } { 2 }, 23\frac { 2 } { 3 } and 34\frac { 3 } { 4 } respectively assert that a ball drawn from the bag is white, the probability of truth of their assertion, is

A

9697\frac { 96 } { 97 }

B

2425\frac { 24 } { 25 }

C

120\frac { 1 } { 20 }

D

67\frac { 6 } { 7 }

Answer

9697\frac { 96 } { 97 }

Explanation

Solution

P(5)= 12×23×3412×23×34+(14)3×12×13×14×4\frac { \frac { 1 } { 2 } \times \frac { 2 } { 3 } \times \frac { 3 } { 4 } } { \frac { 1 } { 2 } \times \frac { 2 } { 3 } \times \frac { 3 } { 4 } + \left( \frac { 1 } { 4 } \right) ^ { 3 } \times \frac { 1 } { 2 } \times \frac { 1 } { 3 } \times \frac { 1 } { 4 } \times 4 }= 9697\frac { 96 } { 97 }