Question

A bag contains 4 white and 3 black balls. If two balls are drawn simultaneously, then the probability that the balls are of different colours is

• A. 3/7
• B. 1/7
• C. 2/7
• D. 4/7

Answer 1

Answer: (D)

4/7

Answer 2

P (getting both different colours) = 1 – P

(both are same colours) = 1 - $\frac { 3 } { 7 } = \frac { 4 } { 7 }$