Question

A bag contains 4 white, 5 red and 6 green balls. Three balls are picked up randomly. The probability that a white, a red and a green bal l is drawn is

• A. $\frac { 15 } { 91 }$
• B. $\frac { 30 } { 91 }$
• C. $\frac { 20 } { 91 }$
• D. $\frac { 24 } { 91 }$

Answer 1

Answer: (D)

$\frac { 24 } { 91 }$

Answer 2

Required probability $= \frac { 4.5 .6 } { { } ^ { 15 } C _ { 3 } } = \frac { 24 } { 91 }$